how to make Xrm.webApi calls response synchronous with other code in a function without using async or await keword

(0) Share

Report

Posted on by ShubhamJain7

Please can someone help me to make a kind of intermediate function or way by which we can call the function having Xrm.webApi call synchronously in any synchronous function without the use of async or await keywords in the existing functions name(in intermediate function async and await will work) like below :

function show(){

//code

var result=function webapicall(); // result:undefined error as it doesn't wait for api call to finish and move to next statement as the xrm.webApi calls are asynchronous, please help me in writing such code without async or await keywords which will execute this synchronously.

alert();

//synchronous code

//more code

}

function webapicall()

{

xrm.webApi.retrievemultiplerecords().then(successcallback,error function)

return response;

}

I have the same question (0)

All responses (6)

Answers (1)

Suggested answer

a33ik 84,331 Most Valuable Professional on at

Like (1)

Report

Hello,

I'm afraid you won't be able to do that in a direct way. You will have to use either async/await or promises.

Was this reply helpful? Yes No
ShubhamJain7 20 on at

Like (0)

Report

Thanks Andrew, Could you please share a sample code to handle this with promises as when i am trying with .then() ..i am getting error :cannot read property than of null....

Below is my code for reference

function getRecord()
{

var b=show().then(function success(result){;
var fetchXml= "<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>"+
" <entity name='account'>" +
" <attribute name='name' />" +
" <attribute name='telephone1' />" +
" <attribute name='address1_city' />" +
" <attribute name='primarycontactid' />" +
" <attribute name='statecode' />" +
" <filter type='and'>" +
" <condition attribute='name' operator='like' value='Adventure Works'/>" +
" </filter>" +
" </entity>"+
"</fetch>";
fetchXml ="?fetchXml=" + encodeURIComponent(fetchXml);
var account="account";
var records=parent.Xrm.WebApi.retrieveMultipleRecords(account, fetchXml);
parent.Xrm.WebApi.retrieveMultipleRecords(account, fetchXml).then( function success(response){

alert("getRecord");
alert("namaste"+response.entities[0].name);
},
function (error) {
alert(error.message);
}
);
});

}

function show()
{

var fetchXml= "<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>"+
" <entity name='account'>" +
" <attribute name='name' />" +
" <attribute name='telephone1' />" +
" <attribute name='address1_city' />" +
" <attribute name='primarycontactid' />" +
" <attribute name='statecode' />" +
" <filter type='and'>" +
" <condition attribute='name' operator='like' value='Adventure Works'/>" +
" </filter>" +
" </entity>"+
"</fetch>";
fetchXml ="?fetchXml=" + encodeURIComponent(fetchXml);
var account="account";
var response=null;
parent.Xrm.WebApi.retrieveMultipleRecords(account, fetchXml).then(
function first(result) {
alert("show");
response=result.entities;

return response;
},
function (error) {

}
);

return response;
}

Was this reply helpful? Yes No
Verified answer

a33ik 84,331 Most Valuable Professional on at

Like (2)

Report
The main reason why your code doesn't work the right way is that the show method has to return the Promise instead of the data itself. I refactored the code of the show function:

function show() { var fetchXml= "" " " " " " " " " " " " " " " " " " " " " ""; fetchXml ="?fetchXml=" encodeURIComponent(fetchXml); var account="account"; return new Promise(function(resolve, reject) { parent.Xrm.WebApi.retrieveMultipleRecords(account, fetchXml).then( function (result) { var response=result.entities; resolve(response); }, function (error) { reject(error); }); }); }

Was this reply helpful? Yes No
ShubhamJain7 20 on at

Like (0)

Report

Thanks Andrew , it worked but if i want to store the response in the calling variable than is it possible like

var b=show().then(function success(result){});

synchronous code

and rest of the synchronous code...?

Was this reply helpful? Yes No
Suggested answer

a33ik 84,331 Most Valuable Professional on at

Like (2)

Report

That won't work as I mentioned in my first reply.

Put your sync code into success handler. Something like

show().then(function success(result){

//your sync code here

});

Was this reply helpful? Yes No
ShubhamJain7 20 on at

Like (0)

Report

Thanks Andrew

cheers !!

Was this reply helpful? Yes No