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Small and medium business | Business Central, N...
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Business Central FLF licensing key generation

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Posted on by 891

My colleague, who raises BC Licences has been asked to create a BC V20 FLF licence for an On-Prem installation containing a list of specific ID's all in the customization range 50000 to 99999. However, he has reported: 'I do not control or enter anything to do with permissions in the FLF so cannot influence it in any way'. My only option is to add the third party app from the drop down and include isv.

I've added a screenshot of the licence tool below. Where would one specify ID's to include and their permissions? 

pastedimage1673622558256v1.png

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  • Suggested answer
    Ben Baxter Profile Picture
    6,620 Super User 2025 Season 2 on at

    Since this is an On-Premise license, it is managed in Microsoft's Partner Source Business Center (PSBC).  As a partner, you do have control over the custom development object ranges.  Again, since it is on-premise the Customer must own the number of development objects you are trying to assign to the license.

    To manage the license, go to the "Manage Custom Area Object" link on the Customer Summary page.

  • Nick Webb Profile Picture
    891 on at

    Thanks for your helpful response. In terms of the permissions for each type, I used the 'Generate permission set as AL object containing current extension objects' in Visual Studio Code and it created the lines below:-

    Permissions = tabledata TrialBalanceByDim=RIMD,
    tabledata TrialBalByDimParams=RIMD,
    table TrialBalanceByDim=X,
    table TrialBalByDimParams=X,
    report CustomTrialBalanceByDim=X,
    codeunit CustomTrialBalancePopulator=X,
    page TrialBalanceByDim=X,
    page TrialBalByDimParams=X,
    query GleDv1=X;

    so, this seems to indicate that for object types: table, report, codeunit, page & query the only permission required is ‘Execute: Yes’. And for TableData: RIMD.

    Is that correct for this example?
    Would this be correct for all extensions or would each project differ?

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