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ReportHow to store the guid of cloned record in the parent record so that we can use the guid to open the created case form?
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How to store the guid of cloned record in the parent record so that we can use the guid to open the created case form?
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Hello,
Thanks for your response!
I am able to clone the records but facing problem while opening created record in same window. I am able to open newly created cloned record in new window but I want in same (can be in different tab). I have tried Xrm.Utility.openEntityForm("incident", guid) and Xrm.Navigation.openUrl(url) but it is getting into different window.
Could you please suggest something how can I open record in same window.
I would suggest to regroup. Based on your code all your cloning is happening inside workflow. You can do following - use action instead of workflow with output of Lookup, EntityReference type. In this way you can do both - cloning and obtaining of resulting record id. Good luck.
new_guid is the hidden field in the case form. I want it to be populated with the guid of the cloned record when the workflow is executed but I am not able to populate the field new_guid. If anyhow I am able to get new_guid, I can open the cloned record form.
So the problem is how to retrieve new_guid.
How can i get the record id in the look up field and what shall i populate from the workflow?
https://community.dynamics.com/crm/f/117/p/236706/822028#822028
Thanks!
Hello Andrew,
I am using the following code to clone the case record. While opening the cloned record, I need new guid. Can you please help me in that.
function ShowAlert_CloneCase() {
debugger;
Alert.show("Do you want to clone this existing case?", "", [
new Alert.Button("Clone", onAlertCloneButton), new Alert.Button("Cancel")
], "Info");
}
function HideAlert() {
Alert.hide();
}
function onAlertCloneButton() {
debugger;
Process.callWorkflow("6B537EDB-E446-442F-89FE-E993D05271B9",
Xrm.Page.data.entity.getId(),
function success() {
debugger;
alert("Workflow executed successfully");
try {
var url = "";
var guid = "";
if (Xrm.Page.getAttribute("new_guid") != null && Xrm.Page.getAttribute("new_guid").getValue() != null) {
url = Xrm.Page.getAttribute("new_guid").getValue();
var preUrl = url.substr(0, url.length - 55);
// Retrievinmg Guid - 184f3bc9-5d83-e811-81a1-0050568a58b2
guid = preUrl.substr(66);
Xrm.Page.getAttribute("new_waguid").setValue(guid);
// opening the newly created record using the guid
var windowOptions = { openInNewWindow: true }; Xrm.Utility.openEntityForm("incident", guid, null, windowOptions);
}
}
},
function () {
debugger;
alert("Error executing workflow");
});
}
function onAlertCloseButtonClick(args) {
Alert.hide();
}
Thanks!
Can you please post a code that should open record form? This is what you should use - msdn.microsoft.com/.../jj602956.aspx
Hello Andrew,
Thanks for the suggestion.
I am trying to clone the case record using javascript on the click of button and open the created record form but I am not able to open the form. Could you please suggest any solution to that.
Thanks!
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André Arnaud de Cal...
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