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Dynamics 365 Community / Forums / Small and medium business | Business Central, N... / Line Break when sendin...
Small and medium business | Business Central, N...
Answered

Line Break when sending data through JSON

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Posted on by IM-18071459-0 45
Hello,

i am using Microsoft Dynamics NAV 2017 version.

I am sending data through JSON.

Variable: JsonTextWriter
Datatype: DotNet
Subtype: Newtonsoft.Json.JsonTextWriter.'Newtonsoft.Json, Version=6.0.0.0, Culture=neutral, PublicKeyToken=30ad4fe6b2a6aeed'

JsonTextWriter.WriteValue(TextField1 + '\n' + TextField2 + '\n'+ TextField3);

The output comes in one single line, but i want it to be break and go on another line after each TextField

TextField1
TextField2
TextField3

any suggestions?
Categories:
Microsoft Dynamics NAV
I have the same question (0)
  • Sohail Ahmed Profile Picture
    Sohail Ahmed 11,136 Super User 2025 Season 2 on at 
    procedure ReadAsTextWithSeparator(InStream: InStream; LineSeparator: Text) Content: Text
    var
        Tb: TextBuilder;
        ContentLine: Text;
    begin
        InStream.ReadText(ContentLine);
        Tb.Append(ContentLine);
        while not InStream.EOS do begin
            InStream.ReadText(ContentLine);
            Tb.Append(LineSeparator);
            Tb.Append(ContentLine);
        end;

        exit(Tb.ToText());
    end;
     
     
     
     
     
    procedure LFSeparator(): Text[1]
        var
            LF: Text[1];
        begin
            LF[1] := 10; // Line feed, '\n'
            exit(LF);
        end;
     
     
    ✅ Mark this answer as verified if it helps you.
  • IM-18071459-0 Profile Picture
    IM-18071459-0 45 on at
    hi Sohail.. i did as you suggested.
     
    StringBuilder.Append('Msg1');
    StringBuilder.Append(10);
    StringBuilder.Append('Msg2');
    StringBuilder.Append(10);
    StringBuilder.Append('Msg3');
    ToSend:=StringBuilder.ToString();
    JsonTextWriter.WriteValue(ToSend);
     
    the output is: Msg1Msg2Msg3
  • Verified answer
    Sohail Ahmed Profile Picture
    Sohail Ahmed 11,136 Super User 2025 Season 2 on at
    StringBuilder.Append('Msg1');
    StringBuilder.Append(CRLFSeparator());
    StringBuilder.Append('Msg2');
    StringBuilder.Append(CRLFSeparator());
    StringBuilder.Append('Msg3');
    ToSend := StringBuilder.ToString();
    JsonTextWriter.WriteValue(ToSend);
     
     
    i guess you missed 2nd portion of my code.
     

    Tip for Debugging

    If you're still seeing the result as a single line in JSON:

    • Confirm that the consumer of the JSON (e.g., a browser, API, or viewer) renders line breaks, as some systems escape them visually.
    • Check if JsonTextWriter.Formatting is set to None or Indented — for visual inspection, Indented helps.
     

    ✅ Mark this answer as verified if it helps you.

     
  • Verified answer
    IM-18071459-0 Profile Picture
    IM-18071459-0 45 on at
    Hi Sohail,
     
    thanks a lot :) It works now.
     
    below the codes:
     
    StringBuilder.Append('Msg1');
    StringBuilder.Append(CRLFSeparator());
    StringBuilder.Append('Msg2');
    StringBuilder.Append(CRLFSeparator());
    StringBuilder.Append('Msg3');
    ToSend := StringBuilder.ToString();
    JsonTextWriter.WriteValue(ToSend);
     
     
    LOCAL CTRLFSeparator() LF : Text[1]
    LF[1]:=10;
    EXIT(LF);
  • Sohail Ahmed Profile Picture
    Sohail Ahmed 11,136 Super User 2025 Season 2 on at
    @IM-18071459-0 Glad it helped you 

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