Unable to get property 'setVisible' of undefined or null reference...

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Posted on by USA80

When I load a record in CRM 2016, I am getting an error, "Unable to get property 'setVisible' of undefined or null reference" I hit F12 to go through the debugger, but it doesn't go through it at all...it just pops up with the same error everytime. This code works just fine in another environment...any ideas why it wouldn't work in my Dev environment?

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gdas 50,091 Moderator on at

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Hi,

setVisible is undefined that means control is getting null in your code so that's why setVisible is undefined.

Could you please share your code.

In addition you can try to add setVisible line inside settimeout so that control will get.

Make sure don't forget to do null and undefined check of control object before doing setVisible.

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Akanksha Ranjan 460 on at

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Hi,

In your code check the below mentioned condition before taking an action.

function test(){

var checkValue = Xrm.Page.getAttribute("new_attribute").getValue();

if (checkValue != null || checkValue != 'undefined' || checkValue !=''){

rest of the code here

}

}

Thanks

PS: Please mark the answer as verified if found helpful.

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Hameed Hussain 250 on at

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The reason is your control object is returning a null and you're appending the 'setVisible' to a null object.

Example - var obj = Xrm.Page.getControl("control_name").setVisible(false);

In this case, the part Xrm.Page.getControl("control_name") is returning a null, and hence the error. The reason could be you have spelled the "control_name" incorrectly or that control doesn't exist anymore.

What you have to do:

if(Xrm.Page.getControl("control_name") != null)

{

Xrm.Page.getControl("control_name").setVisible(false);

}

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Nithya Gopinath 17,078 on at

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Hi,

Javascript function on-load of the form has a control which is null or undefined (maybe because you haven't added the control to form or the name of the control is not correct).

Please check the condition as follows.

var control = Xrm.Page.getControl("controlName"); if((control ! = null) && (control != undefined)) { control.setVisible(true); }

Hope this helps.

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Mohsin Ali 3,634 on at

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It mean you don't have placed the field that you want to setVisible true or false. Also, in your source code you need to add keyword debugger; and then press F12 to see the debug your source code.

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USA80 26 on at

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The issue was because I had the same function name in another script that was on load. Once I changed one of the function name to something else, it loaded fine.

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a33ik 84,331 Most Valuable Professional on at

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If you got an answer (even you answered it) please verify it.

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USA80 26 on at

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I did already. Does it not show that?

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a33ik 84,331 Most Valuable Professional on at

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I don't want to argue. I closed the thread. Please close your threads in future. Just friendly advice.

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USA80 26 on at

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oh, no worries. I did verify the answer, just didn't close the thread. Sorry, thanks for the heads up.

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