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ReportThe error that pops up is the following:
And when I do debuging this error prompts up.
Can anyone please tell me what to do!!
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The error that pops up is the following:
And when I do debuging this error prompts up.
Can anyone please tell me what to do!!
*This post is locked for comments
I have the same question (0)
The error means that there already is a record with the same value in a unique (not necessarily primary) index. The database server makes sure that unique indexes contain unique values, therefore such a record can't be inserted.
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