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Finance | Project Operations, Human Resources, ...
Suggested Answer

Active buffer required

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Hi. I have a problem when I am trying open the form I got this error - "Active buffer required". Any ideas. Working with Microsoft Dynamics 2012 R3.

I have the same question (0)
  • Blue Wang Profile Picture
    Microsoft Employee on at

    Hi Zymantas,

    What form are you opening?

    It needs to pass records.

    It should be a subform that generally jumps through other forms and carries the record.

  • Suggested answer
    nmaenpaa Profile Picture
    101,166 Moderator on at

    You can look into the init method of the form. There you will find the check that throws this error. The form is designed to be opened by passing a record  (buffer) into it.

    By the way, please use only relevant tags in your question. Seems you have now selected many unrelevant tags, such as "Administration and Setup", "Connector for CRM", "Enterprise Portal" and many more.

  • Blue Wang Profile Picture
    Microsoft Employee on at

    Hi Zymantas,

    Please refer this :mansoorgee.blogspot.com/.../dynamics-ax-form-requires-active-buffer.html

  • Community Member Profile Picture
    on at

    My form's init method look that:

    public void init()

    {

       ConFMSVehicleTable callerVehicle;

       super();

       switch(element.args().dataset())

       {

           case tableNum(ConFMSVehicleTable):

               callerVehicle =element.args().record();

               break;

       }

       if(callerVehicle.RecId == 0)

       {

           throw error("@SYS79604");

       }

       contract = ConFMSVehicleGroupChangeContract::construct();

       contract.vehicleId(callerVehicle.VehicleId);

       contract.vehicleGroupId(callerVehicle.VehicleGroupId);

    }

  • Suggested answer
    nmaenpaa Profile Picture
    101,166 Moderator on at

    As you can see, you need to provide a record of ConFMSVehicleTable, otherwise the form can't be opened.

  • Community Member Profile Picture
    on at

    As I understood I should insert new record ConfFMSVehicleTable table, right?

  • Suggested answer
    nmaenpaa Profile Picture
    101,166 Moderator on at

    Not necessarily. But you need to have a record in that table, and send that record to this form when you open this form.

    This form is designed to work with a vehicle record.

    I can guess that you have a button that opens this form. This button is on some other form, where you have a list of vehicles. Is this correct? If yes, the button group on the vehicle form should have property DataSource set to point to the vehicle table data source.

    If you still have problems, please share more information about these forms, and your business requirement.

  • Community Member Profile Picture
    on at

    I have inserted some records and form still not valid to open. It has no relations with others forms. CONFMSVehicleTable has several records.

  • Suggested answer
    nmaenpaa Profile Picture
    101,166 Moderator on at

    Did you read my previous post?

    It's not about having data in that table, it's about providing one record from that table when you open the form! The form can only be opened if you provide a context for a single record in the vehicle table.

    Please read through the given replies one more time.

    Also, if this form was developed in your company, perhaps you could ask your colleagues if you still feel you need some help. Or, at least share with us your business requirement and the purpose of this form. Thanks in advance!

  • Community Member Profile Picture
    on at

    My init code: public void init()

    {

       ConFMSVehicleTable callerVehicle;

       super();

       switch(element.args().dataset())

       {

           case tableNum(ConFMSVehicleTable):

               callerVehicle =element.args().record();

               break;

       }

       if(callerVehicle.RecId == 0)

       {

           throw error("@SYS79604");

       }

       contract = ConFMSVehicleGroupChangeContract::construct();

       contract.vehicleId(callerVehicle.VehicleId);

       contract.vehicleGroupId(callerVehicle.VehicleGroupId);

    }

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