How can I shorten this loop in python?

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Posted on by ZainUlAbdeen

I'm working on a "word generator" But I have a problem. Sometimes it creates unwanted words. I would like to remove them but not to heavy the loop.

I have to do like the example in the code with the whole alphabet. There would be nothing wrong with it that much, but there are a few other problems that I would have dealt with if only I knew how to cut it short.

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# alph = "abcdefghijklmnopqrstuvwyzxą"

my_var = ["abc", "aabc", "cbd", "ccbd", "qwe", "qqwe"]
my_var2 = []


def removeDup():
for x in my_var:
if x.find("aa") == -1 and x.find("cc") == -1 and x.find("qq") == -1:
my_var2.append(x)
print(my_var2)

removeDup()

My idea is dynamic variables, but I can't make one loop in the other without creating chaos I tried something like the one in the picture, but I can only take out words with repeated letters

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RE: How can I shorten this loop in python?

Hi ZainUlAbdeen,

The output of your code is ['abc', 'cbd', 'qwe'], which is not you want to achieve?

If so, please tell us what you want to get, a string result 'abcdqwe'?