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Multiple Vendors with Different Costs & Lead times?

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Hi All,

This is my first time posting on these forums but I was wondering if someone could assist me with a problem I’m having in NAV 2017.

I am an absolute novice with NAV and am only muddling my way through things at the moment, but I am coming across an issue with having multiple vendors for single item card.

To give a bit of background, the company I have joined was quote old fashioned and have been forced into using NAV. When they bean creating item cards for the products they sold they would create multiple item cards of the same product but have each one coming from a different supplier at different costs & selling price. Obviously this has created a huge amount of duplicates within NAV and new people joining the company can get confused when selecting item card to place on sales quotes.

I was wondering if it was possible to set up multiple vendors/suppliers on a single item card which you could switch between when the need called for it. For example, if I am selling a 450X450 Metal Duct that I normally get from “Superduct” but I they are out of stock and I need to change to “Notsuperduct” I want to be able to select “Notsuperduct” from a list and have all my costs & lead times automatically adjusted to reflect the different supplier. Is this possible?

I have followed the instructions on this link (https://learn.microsoft.com/en-gb/dynamics-nav-app/inventory-how-register-new-items) but it doesn’t appear to work, however I can’t be sure I’m following it correctly as it doesn’t ask for new costs or lead times, just vendor names.

Any help would be very much appreciated.

Thanks 😊
  • Suggested answer
    YUN ZHU Profile Picture
    YUN ZHU 73,565 Super User 2024 Season 2 on at
    Multiple Vendors with Different Costs & Lead times?
    Hi, you can try the Item Cross Reference feature, this is a standard feature and you can enter different No. and Description for different vendors.
     
    In addition, if you need different costs, you can try the Item Variant function.

    Hope this helps.
    Thanks.
    ZHU

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