System.Text.Json JsonSerializer::Deserialize(string, type) return empty

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Posted on by Yue Zhen

Hi experts,

I am calling the API from X++ Dynamics 365 FO. After the POST request is sent, the API will return a JSON with 4 variables to me, which are Access Token, Expires In, Token Type and Scope. However, when I tried to deserialize it, it returns empty as shown in the debug output window.

I would like to ask how can I deserialize the JSON string in X++.

I have the Token class written in X++ as follow:

using System.Attribute;
using System.Text.Json;
using System.Text.Json.Serialization;

public class Token
{
public str accessToken;
str tokenType;
int expiresIn;
str scope;

[JsonPropertyName(/access_token/)]
public str AccessToken(str _accessToken = accessToken)
{
accessToken = _accessToken;
return accessToken;
}

[JsonPropertyName(/token_type/)]
public str TokenType(str _tokenType = tokenType)
{
tokenType = _tokenType;
return tokenType;
}

[JsonPropertyName(/expires_in/)]
public int ExpiresIn(int _expiresIn = expiresIn)
{
expiresIn = _expiresIn;
return expiresIn;
}

[JsonPropertyName(/scope/)]
public str Scope(str _scope = scope)
{
scope = _scope;
return scope;
}

}

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Yue Zhen 79 on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

It is a StreamReader.

System.Net.WebRequest webReq = WebRequest::Create(strFmt("https://%1/connect/token", ads_EinvParms.ads_BaseURL));

System.IO.Stream streamStr, responseStr;
System.IO.StreamWriter streamWriter;
System.Net.WebResponse webResponse;
System.IO.StreamReader reader;
Martin Dráb 229,275 Most Valuable Professional on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

Yes, your code assumes it's a JSON string. But what is the actual value? If we want to understand why the string failed to parse, we need to know what data we're talking about.
Yue Zhen 79 on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

Good morning, Sir Martin

System.Text.Json.JsonSerializerOptions options;

System.Net.WebRequest webReq = WebRequest::Create(strFmt("https://%1/connect/token", ads_EinvParms.ads_BaseURL));

System.IO.Stream streamStr, responseStr;
System.IO.StreamWriter streamWriter;
System.Net.WebResponse webResponse;
System.IO.StreamReader reader;

webReq.set_Method("POST");
webReq.set_ContentType('application/x-www-form-urlencoded');
streamStr = webReq.GetRequestStream();
streamWriter = new System.IO.StreamWriter(streamStr);
streamWriter.Write(strFmt("client_id=%1&client_secret=%2&grant_type=client_credentials&scope=InvoicingAPI", ads_EinvParms.ads_ClientID, ads_EinvParms.ads_ClientSecret));
streamWriter.Flush();
streamWriter.Close();
streamWriter.Dispose();

webResponse = webReq.GetResponse();
responseStr = webResponse.GetResponseStream();
reader = new System.IO.StreamReader(responseStr);
info(reader.ReadToEnd());

The value of the first parameter I put is reader.ReadToEnd(), it should be a string.
Martin Dráb 229,275 Most Valuable Professional on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

What is the value of the first parameter?
Yue Zhen 79 on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

I declare the option and add to JsonSerializer.Deserializer.

options = new System.Text.Json.JsonSerializerOptions();
options.NumberHandling = JsonNumberHandling::AllowReadingFromString;

myToken = System.Text.Json.JsonSerializer::Deserialize(reader.ReadToEnd(), myToken.GetType(), options);

however, it return the error states that "System.Text.Json.JsonException: The input does not contain any JSON tokens. Expected the input to start with a valid JSON token, when isFinalBlock is true. Path: $ | LineNumber: 0 | BytePositionInLine: 0."
Martin Dráb 229,275 Most Valuable Professional on at

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

According to documentation of Deserialize(), there is no overload accepting String and Type. Use one of the existing overloads, e.g. Deserialize(String, Type, JsonSerializerContext).

System.Text.Json JsonSerializer::Deserialize(string, type) return empty

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System.Text.Json JsonSerializer::Deserialize(string, type) return empty

Helpful resources

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Dynamics 365 Community Platform update – Oct 28

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