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Adding new custom personnel action d365fo using x++

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Posted on by MS-29011540-0

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Hello,
Is it possible to add a new custom personnel action in d365fo?

The already existing types are workers (hiring, transfers, and terminations), positions (creating and editing) and change fixed compensation.

Can I create a new type like editing a worker?

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Dynamics 365 Finance

Dynamics 365 Human Resources

Microsoft Dynamics AX

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Sohaib Cheema 49,438 User Group Leader on at

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could you retry, rephrasing your question please. what do you mean by type ?

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MS-29011540-0 269 on at

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@Sohaib Cheema
Sure,
I mean here

Adding a fully customized personnel action for editing worker data, and to work like modify position for example.

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Sohaib Cheema 49,438 User Group Leader on at

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On the surface it looks possible as this is a Base Enum , which you can extended. However you would need to look at all references for this base enum, to make sure if it needs code extended anywhere else in the system.

Say for example if this being used in class/method with if conditions or using Switch statement , you would want to add your new element as well.

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Raj Borad 1,424 on at

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Hi @MS-29011540-0,

As earlier suggested by @Sohaib Cheema, you can add a new custom personal action.
I just want to know the purpose/requirement of this custom action. If required then you also need this new action to trigger a workflow like existing ones?

Thank you,

Raj D Borad

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MS-29011540-0 269 on at

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@Sohaib Cheema
Yes, but no documentation to create it from scratch, i fear i miss some references and don't have the full visions for the stagging tables. forms. ...
Anyway thanks alot
@Raj Borad Yes, the client wants exactly the edit employee action to act as any other out-of-box actions

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Suggested answer

Cyrille Nembot 149 on at

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The personnel actions framework is
extensible, allowing you to create new action types like "Editing a
Worker" beyond the standard options.

Implementation Approach

To create a custom personnel action type:

Extend the PersonnelActionType base enum:

x++

[ExtensionOf(enumStr(PersonnelActionType))] public final class MyPersonnelActionType_Extension { public const MyEditWorkerAction = 20; // Use next available number }

Create a new class that extends PersonnelAction:

x++

class MyEditWorkerPersonnelAction extends PersonnelAction { // Implement required methods public PersonnelActionType actionType() { return PersonnelActionType::MyEditWorkerAction; } // Add other required logic }

Register your action in the PersonnelActionController class initialization:

x++

personnelActionProcessorMap.insert(PersonnelActionType::MyEditWorkerAction, classStr(MyEditWorkerPersonnelAction));

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Martin Dráb 237,807 Most Valuable Professional on at

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@Cyrille Nembot Don't forget Responsible AI policies, such as disclosing the use of AI and verifying the correctness of your reply.

Unfortunately, your reply is complete AI halucination and therefore not helpful to anyone.

For example, the first code snippet shows a completely wrong way of extending an enum; this approach isn't possible in F&O. The constant is also missing a data type. The second code snipper suggests extending PersonnelAction, but no such a class exists. Then you suggest using PersonnelActionController class, but it doesn't exist either...

1 people found this reply helpful.

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