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Dynamics 365 Community / Forums / Microsoft Dynamics AX (Archived) / TreeNode AOTgetPropert...
Microsoft Dynamics AX (Archived)

TreeNode AOTgetProperty("Model") return different values on Client and Server

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Posted on by EugeneVoloshchenko 52

Hello, everyone!

The subject is next:
I'm creating instance of TreeNode object. It has property "Model". On client this property has value "Foundation". On server this property has value "19". (values provided for example).
So, the problem is when I call method AOTgetProperty("Model") it returns "Foundation" on Client and "19" on Server.

Example of code:

TreeNode treeNode;
ModelName modelNameRet;

treeNode = TreeNode::findNode(@"\Data Dictionary\Base Enums\ABC");

modelNameRet = parentTreeNode.AOTgetProperty("Model");

info(modelNameRet);

*This post is locked for comments

I have the same question (0)
  • Mea_ Profile Picture
    Mea_ 60,284 on at

    Hi EugeneVoloshchenko,

    It would be nice if you explain what you are  actually doing and what you want to achieve. 

  • EugeneVoloshchenko Profile Picture
    EugeneVoloshchenko 52 on at

    I need to get Model name of an object. And I need to put Model name of an object to my table. I don't need to get model ID.

    For this purpose I create TreeNode object from AOT path. I run my code in batch, so the problem I described above occures.

  • Verified answer
    Mea_ Profile Picture
    Mea_ 60,284 on at

    I don't know the answer and I don't think that someone except MS really knows it. 19 is a model id for Foundation and you can get a name using SysModelStore::modelId2Name() static method.

    However, I would not use TreeNode API at all and go though SysModelElement that gives you same result on client and server:

        SysModelElement         sysModelElement;
    SysModelElementData     sysModelElementData;
    utilModels              utilModels;

    
    select sysModelElement
        where sysModelElement.Name == "ABC"
            join sysModelElementData
                where sysModelElement.RecId == sysModelElementData.ModelElement
                    join Name from utilModels
                        where utilModels.Id == sysModelElementData.ModelId;
    
    info (utilModels.Name);

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