Pass System.IO.Stream to BinData

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Posted on by Abhinay Tharwal

1,215

Hi,

Greetings!

I am getting a System.IO.Stream object stored in Azure storage and in another method I have uploaded it to another location, which means the file get works fine.

Now I have to send a base64Encode of BinData object. I tried the following code but it fails at Binary binaryStream = Binary::constructFromMemoryStream(stream);

System.IO.Stream stream = //get file stream;

if(stream.CanSeek)
{
    stream.Seek(0, System.IO.SeekOrigin::Begin);
}
Binary binaryStream = Binary::constructFromMemoryStream(stream);
binData = new BinData();

container conBinData = binaryStream.getContainer();

binData.setData(conBinData);

container data = [binData.base64Encode()];

With best regards,

Abhinay

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Martin Dráb 237,880 Most Valuable Professional on at

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Please tell us more about the problem than just "it fails". I guess you get a runtime exception - what is its type and message?

It the stream really a MemoryStream?

Also, do you really must use BinData? For example, is using System.Convert::ToBase64String() impossible in your case?

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Abhinay Tharwal 1,215 on at

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Hi Martin,

Thank you for your reply.

The error message does not say much

Exception thrown: 'System.ArgumentException' in Microsoft.Dynamics.AX.Xpp.Support.dll {"Exception has been thrown by the target of an invocation."}

I tried this code too:

System.IO.MemoryStream memoryStream = stream as System.IO.MemoryStream; Binary binaryStream = Binary::constructFromMemoryStream(memoryStream);

//BR, Abhinay

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Martin Dráb 237,880 Most Valuable Professional on at

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You get more from the exception, e.g. checking inner exception and stack traces.

The "as" operator won't magically convert object from one to another. Also, you said you tried the code, but you forgot to tell us what happened. My guess is that you get an empty value in memoryStream variables. If so, it confirms my suspicion that it's not a MemoryStream instance, and it explain why the whole thing can't work.

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Abhinay Tharwal 1,215 on at

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Hi Martin,

Thank you for your suggestion.

The line I had to add was:

stream.CopyTo(memoryStream);

So, the code would be:

System.IO.MemoryStream memoryStream = new System.IO.MemoryStream(); stream.CopyTo(memoryStream); Binary binaryStream = Binary::constructFromMemoryStream(memoryStream);

//BR, Abhinay

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