Microsoft Dynamics AX (Archived)

Disable Button when Selecting Data

(0) Share

Report

Posted on by XSpy

209

Hello All,

I need help here.

1817.Q.png

Warehouse management > Common > Load planning workbench

If the Load Status is "Open", then the Release Button must be Enabled (Default).
If the Load Status is Not "Open", then the Release Button must be Disabled.

must be triggered upon clicking a data.

is this possible?

Please help, thanks.

*This post is locked for comments

I have the same question (0)

All responses (8)

Answers (1)

Suggested answer

5400 7,162 on at

Like (0)

Report

Yes,It is possible. you can achiev through active method which will be good pratice this type scenarion. But if you want through button click also possible.

Make release button - as autodiclartion yes

and put the logic.

Was this reply helpful? Yes No
Sohaib Cheema 49,438 User Group Leader on at

Like (0)

Report

of course, on any form buttons can be enabled/disabled by writing code at active() method.

But, very important thing is to know/read existing logic. how your code will behave in combination with existing business process? are those buttons already being enabled/disabled by any business process? these questions must be answered before you start writing code at active() method.

sometimes form(s) do have a interaction class, where the buttons enable/disable is being handled based on many aspects, those need review.

it is not about possible/impossible. its about reading your customization in combination with existing business process.

Was this reply helpful? Yes No
XSpy 209 on at

Like (0)

Report

the Release button is always Enabled, I just want to add the Disable function.

can you help me with the code? thanks.

Was this reply helpful? Yes No
Sohaib Cheema 49,438 User Group Leader on at

Like (0)

Report

check if there is existing active method on datasource; if not do override it by right clicking methods node of datasource, and then write code after super() as under

if(condition)

{

ButtonName.enabled(true);

}

else

{

ButtonName.enabled(false);

}

Was this reply helpful? Yes No
Verified answer

5400 7,162 on at

Like (0)

Report

Please go to

\Forms\WHSLoadPlanningWorkbench\Designs\Design\[Tab:DemandLoadsTab]\[TabPage:TabLoad]\[ActionPane:ActionPaneLoad]\[ActionPaneTab:ActionPaneTabLoad]\[ButtonGroup:Info]\[MenuButton:ReleaseMenuButton] -

ReleaseMenuButton - do autodeclartion yes.

\Forms\WHSLoadPlanningWorkbench\Data Sources\WHSLoadTable\Methods\active-- before return write below code

ReleaseMenuButton.enabled(WHSLoadTable.LoadStatus == WHSLoadStatus::Open ? true : false);

Was this reply helpful? Yes No
XSpy 209 on at

Like (0)

Report

Thanks Sohaib Cheema, Bhaskar Roy!

the code works,

but there's one more flaw here.

the WHSLoadTable is linked in the bottom part of the Form (Loads).

the Load status in the upper part is also part of WHSLoadTable, but the active method only works in the bottom part of Form.

i need it to work in the upper Load status, not the bottom one.

*im trying the code :

ReleaseMenuButton.enabled(WHSLoadTable.LoadStatus == WHSLoadStatus::Open ? true : false);

in other DataSource to see if it might work, but might as well ask if you know where to put it.

Was this reply helpful? Yes No
Sohaib Cheema 49,438 User Group Leader on at

Like (0)

Report

we are not sure about status field which is appearing in upper part, as system is in your hand; whether that belongs to WHSLoadTable or some other Datasource

Or may be it is because of upper gird is bound to another dataSource.

from your above screenshot(1st one) it seems that it may be part of SalesLine

Was this reply helpful? Yes No
XSpy 209 on at

Like (0)

Report

yes thanks for the answers, i'll try to put it in every Datasource to try it. Thanks!

Was this reply helpful? Yes No