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Validate the Website Url field using javascript in dynamics crm.
How can i implement this one validation
Can u please help me.
Thank you
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Hello
Validate the Website Url field using javascript in dynamics crm.
How can i implement this one validation
Can u please help me.
Thank you
Thank you Mehran.
ok, use this:
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Answers (
function validURL(str) {
var pattern = new RegExp(http(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9@:%._\ ~#=]{2,256}\.[a-z]{2,6}\b([-a-zA-Z0-9@:%_\ .~#?&\/\/=]*);
return !!pattern.test(str);
}
Regards.
Thank you Mehran.
Very nice update. It is very useful to me.
Your code output displays like this: https://test.in
I need like this format :https://www.test.in
Can u pls help me
Hi,
add this function to OnChange Event of field:
function OnChangeWebSite() {
var webSite = Xrm.Page.getAttribute("webSite");
if (webSite.getValue() != null) {
if (!validURL(webSite.getValue())) {
alert("Please Insert a Valid URL!");
}
}
}
function validURL(str) {
var pattern = new RegExp('^(https?:\\/\\/)?' // protocol
'((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.) [a-z]{2,}|' // domain name
'((\\d{1,3}\\.){3}\\d{1,3}))' // OR ip (v4) address
'(\\:\\d )?(\\/[-a-z\\d%_.~ ]*)*' // port and path
'(\\?[;&a-z\\d%_.~ =-]*)?' // query string
'(\\#[-a-z\\d_]*)?$', 'i'); // fragment locator
return !!pattern.test(str);
}
Best Regards.
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