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How to get the selected record on list page, details on the detail form ?
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Hi,
Can you provide some more details regarding your requirement. Record can be accessed through the formdatasource and you can use following code to loop through the selected records on form.
LocalTablename localTablename; // Declare table variable
Tablename_ds = _salesLine.dataSource();
for (localTablename = Tablename_ds.getFirst(true) ? Tablename.getFirst(true) : Tablename_ds.cursor();
localTablename;
localTablename = Tablename.getNext())
{
//Do your thing
}
you need to link the details form in listpage.
You could find same in standard forms such as salesorder,purchaseorder listpages.
If the requirement is not similar, express more..
I have a list page and a normal form
List page displays data of table A and the other form displays data of table B
both the tables are related through a common field
when I double click the grid of list page the other form opens but it shows all the data in the table B
I want to filter the detail to be shown of that record which is double clicked on the list page
Please try the following statements:
1. Set property CopyCallerQuery to Yes and NeedsRecord to Yes on the first listpage(FormA) MenuItembutton properties.
2. On FormB,In the ClassDeclaration method declare common variable
Common callerRecord; TableA tableA;
In the init method, capture caller record
if (element.args().parm() == formStr(CaseDetail)) { custTable_ds.allowEdit(false); }tableA = TableA::findRecId(callerRecord.RecId); // or write a query based on recordId
In the init method of tableB formdatasource
querybuilddatasourc qbds; Querybuildrange qbr; super(); qbds = this.query().datasourceTable(tablenum(TableB)); qbr = SySquery::findorCreateRange(qbds, fieldnum(TableB, commanField)); qbr.value(queryvalue(tableA.CommonField));
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