How to find Sum of odd and even characters of string

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Posted on by CU02071804-0

Hi,

I have a requirement where I have a string input where I have to find the sum of all even characters and multiply it with 3 and similarly find sum of all odd characters and multiply it with 1 and then sum all of it together and find mod of 10(i.e. if sum of odd + even = 44 then 44 mod 10 = 6, i should get 6 as the output)

How do i achieve the same using x++ code?

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Martin Dráb 239,029 Most Valuable Professional on at

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What do you mean by a sum of characters? Do you expect numbers only and no other characters? Or do you want to support other characters too (e.g. letter, punctuation or so) and somehow convert them to numbers?

Regarding how to iterate characters, this is a native X++ way:

for (int i = 1; i <= strLen(inputString); i++) { subStr(inputString, i, 1); }

Another option is using .NET classes. You could use String.ToCharArray() to convert the string to an array of characters, which then allows you to write logic for indexes that are divisible by two (mod 2) and the rest.

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CU02071804-0 on at

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Hi Martin my requirement says that

if strinput = 2143658790

then evenSum = 1+3+5+7 +0 = 16

evenmultiply = 16*1 = 16

oddSUm = 2+4+6+8+9= 29

oddmultiply = 29*3 = 87

then,

sum = ((16+87) mod 10) = (103 mod 10) = 7

hence sum = 7

This s the mathematical overview of my requirement how do i achieve it through x++

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Martin Dráb 239,029 Most Valuable Professional on at

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I already showed how to get the characters, therefore there are just a few small things to add:
str input = '2143658790'; str numChars = strKeep(input, '0123456789'); if (strLen(input) != strLen(numChars)) { throw error("Input contains invalid characters."); } int oddSum; int evenSum; for (int i = 1; i <= strLen(numChars); i++) { int digit = str2Int(subStr(numChars, i, 1)); if (i mod 2) { evenSum += digit; } else { oddSum += digit; } } int checksum = (evenSum + oddSum * 3) mod 10;

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CU02071804-0 on at

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Thanks Martin

this solves the problem

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CU02071804-0 on at

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Hi Martin how would i achieve it if

if strinput = 2143658790

even str1 = 1*1 =1

even str2 = 3*1 = 3

even str3 = 5*1 = 5

even str4 = 7*1 = 7

3v3n str5 = 0*1 = 0

then evenSum = 2+3+5+7+0 = 16

odd str1 = 2*3 = 6

odd str2 = 4*3 = 12

odd str3 = 6*3 = 18

odd str4 = 8*3 = 24

odd str5 = 9*3 = 27

then oddSum = 6+12+18+24+27 = 87

then,

sum = ((16+87) mod 10) = (103 mod 10) = 7

hence sum = 7

This s the mathematical overview of my requirement how do i achieve it through x++

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Martin Dráb 239,029 Most Valuable Professional on at

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I'm sorry, but it's not clear to me what problem you have.

It seems to be the same thing that we discussed before and you confirmed that the code I gave you did the job.

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CU02071804-0 on at

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Yes Martin the code you gave did the job all i am asking you if we have scenario like the one below how ill we proceed with the code, can you please let me know the x++ code for the scenario.

if strinput = 2143658790

even str1 = 1*1 =1

even str2 = 3*1 = 3

even str3 = 5*1 = 5

even str4 = 7*1 = 7

3v3n str5 = 0*1 = 0

then evenSum = 2+3+5+7+0 = 16

odd str1 = 2*3 = 6

odd str2 = 4*3 = 12

odd str3 = 6*3 = 18

odd str4 = 8*3 = 24

odd str5 = 9*3 = 27

then oddSum = 6+12+18+24+27 = 87

then,

sum = ((16+87) mod 10) = (103 mod 10) = 7

hence sum = 7

This s the mathematical overview of my requirement how do i achieve it through x++

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Martin Dráb 239,029 Most Valuable Professional on at

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Please explain the difference. It looks identical to me.

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CU02071804-0 on at

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i understand here the calculation looks identical but if we consider the scenario of bar code calculation then the output might differ, so considering that i wanted to know the x++ code

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Martin Dráb 239,029 Most Valuable Professional on at

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I'm sorry, but I still don't understand what you want from me. You'll have to be much more specific if you want to get an answer.

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