Syntax for Menu Items (display/output/action) in X++

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Hey all,

I am cycling through the Menu TreeNodes in AX, and I'm unsure how to identify display menu items through my loop. In pseudocode, I am looking for:

if(TreeNode.AOTName() == <Display Menu Item>)

I am looking for what the Syntax would be to make that statement true for <Display Menu Item>.

Thank you

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André Arnaud de Cal... 303,730 Super User 2026 Season 1 on at

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Please elaborate. What is the complete requirement? Are you looking for only menu items of type display or a certain menu item with a specific name?

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Community Member on at

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I am cycling through the <Menus> object within the AOT TreeNode. When you open the folders, you eventually hit Menu Items of various types.

My code already goes through all the folder objects and hits the Menu Items. I want to have a conditional for when I hit a Menu Item. Essentially I would be looking for Menu Items of all types (not just display), but display seems to be the most common.

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Ehtasham Rahman 672 on at

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Can you please paste your piece of code here? It'll help to make me to give you solution.

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Community Member on at

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You bet, here is the code.

Class main:

--------------------------------------------------------------------------------------

public void main()
{
#AOT
TreeNode tNode;
TreeNodeIterator tIterator;
TreeNode controlMenuItemNode;
TreeNode controlNode;

tNode = TreeNode::findNode(strFmt('%1', #MenusPath));

tIterator = tNode.AOTiterator();
controlNode = tIterator.next();

while(controlNode != null)
{

//Display's all items
info(ControlNode.AOTname());

//What I want to display

/*if(ControlNode.AOTname() == <Display Menu Item Syntax>)

{

//Insert Logic here

}

*/
this.iterateTreenode(TreeNode::findNode(strFmt('%1\\%2', #MenusPath, ControlNode.AOTname())));
controlNode = tIterator.next();
}

info('Complete');
}

-------------------------------------------------------------------------------------

Class method 1:

-------------------------------------------------------------------------------------

private void iterateTreenode(TreeNode tNode)
{
#AOT
TreeNodeIterator tIterator;
TreeNode controlMenuItemNode;
TreeNode controlNode;

tIterator = tNode.AOTiterator();
controlNode = tIterator.next();

while(controlNode != null)
{
info(ControlNode.AOTname());
this.iterateTreenode(ControlNode);

controlNode = tIterator.next();
}
}

---------------------------------------------------------------------------

I then call my class through a job

---------------------------------------------------------------------------

static void IterateMenusJob(Args _args)
{
IterateMenusClass im = new IterateMenusClass();
im.main();
}

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reachnaidu 890 on at

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Try this ..

static void searchSubNodes(Args _args)

{

str treeNodeNames;

void searchSubNodes (TreeNode _treeNode)

{

if (!_treeNode)

return;

_treeNode = _treeNode.AOTfirstChild();

while (_treeNode)

{

if (_treeNode.AOTfirstChild())

{

searchSubNodes(_treeNode);

}

if (_treeNode.applObjectType())

{

treeNodeNames += strfmt("%1\n", _treeNode.treeNodeName());

}

_treeNode = _treeNode.AOTnextSibling();

}

}

;

searchSubNodes (TreeNode::findNode(@"\Menu Items"));

info(treeNodeNames);

}

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reachnaidu 890 on at

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A small modification to the above Job :

static void searchSubNodes(Args _args)

{

str treeNodeNames;

void searchSubNodes (TreeNode _treeNode)

{

if (!_treeNode)

return;

_treeNode = _treeNode.AOTfirstChild();

while (_treeNode)

{

if (_treeNode.AOTfirstChild())

{

searchSubNodes(_treeNode);

}

if (_treeNode.applObjectType())

{

treeNodeNames += strfmt("%1 %2\n", _treeNode.treeNodeName(),_treeNode.AOTgetProperty('ObjectType'));

}

_treeNode = _treeNode.AOTnextSibling();

}

}

;

searchSubNodes (TreeNode::findNode(@"\Menu Items"));

info(treeNodeNames);

}

Here we can find the Menu item Type by checking treeNode.AOTgetProperty('ObjectType') which gives either Form,Report or Class.. Based on that you can iterate through display, Output and Action menu items.

Hope this solves your problem.

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Ehtasham Rahman 672 on at

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Try the following job:

static void LoopInAOTByChoice(Args _args)

{

UtilElements UtilElementsLocal;

;

while select * from UtilElementsLocal

where UtilElementsLocal.recordType == UtilElementType::DisplayTool //Set what AOT node you want to loop in

//&& UtilElementsLocal.utilLevel == global::currentAOLayer() //Set this condition if you want to loop in current layer's element

{

info(UtilElementsLocal.name) ;

}

}

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Martin Dráb 239,040 Most Valuable Professional on at

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You might be looking for if (controlNode.AOTname() == menuItemDisplayStr(YourMenuItem)).

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Community Member on at

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It would be close this, but it I would need something logically equal to if(menuItemDisplayStr(controlNode.AOTName())) is valid to check to see if the AOTName() returned is a display menu item. However, it does not work this way because menuItemDisplayStr is an intrinsic function.

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reachnaidu 890 on at

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Did you check this ?

treeNode.AOTgetProperty('ObjectType') which gives either Form,Report or Class.. Based on that we know Form belongs to DisplayMenuitem, Report to Output and Class to Action..

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