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How to addMenuItem in X++ and show button instead of link ?

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Posted on by Teevo

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Hi guys,

When creating class (RunBase class), I'm adding a menuitem in my Dialog like this :

public Object dialog()
{
dialog = super();

DialogGroup dialogGroup = dialog.addGroup('Upload file');
FormBuildControl formBuildControl = dialog.formBuildDesign().control(dialogGroup.name());

dialogJournalNameId = dialog.addField(ExtendedTypeStr(LedgerJournalNameId), /Ledger journal name/);
dialog.addMenuItemButton(MenuItemType::Action, /My_Template/);

return dialog;
}

After run, the addition menu item is displayed as a link. How to make it as a button instead ?

Thanks.

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Layan Jwei 8,280 Super User 2026 Season 1 on at

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Hi Teevo,

I would advise to use sysOperationFramework instead of runBase.

Maybe check if this link is helpful:
https://ariste.info/en/2020/07/add-menu-item-sysoperation-dialog/

if you still want to stick with runBase, I think you should be able to do somehow the same to make it appear as a button.

Thanks,
Layan Jweihan
Please mark this answer as "Verified" if it solved your issue. In order to help others who will face a similar issue in the future.

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Teevo 405 on at

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Hi Layan,

Noted about your advice of using SysOperationFrameWork instead.

However may I know how should I still want to use RunBase ?

Issue is I'm not the original developer but assisting only hence I can't change the existing one and this is using RunBase.

Thanks.

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Mohamed Amine Mahmoudi 26,811 Super User 2026 Season 1 on at

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Hi @Teevo,

Try this :

1 - Dialog method

public Object dialog() { DialogRunbase dialog; DialogGroup dlgGroup; FormBuildGroupControl buttonGroup; FormBuildButtonControl buttonControl; dialog = super(); dialog.caption("Dialog"); dlgGroup = dialog.addGroup('ButtonGroup'); buttonGroup = dialog.formBuildDesign().control(dlgGroup.formBuildGroup().id()); buttonControl = buttonGroup.addControl(FormControlType::Button, 'Button Name'); buttonControl.registerOverrideMethod(methodStr(FormButtonControl, clicked), methodStr(YourClass, YourClickedMethod), this); return dialog; }

2 - Clicked method

private void YourClickedMethod(FormButtonControl _formButtonControl) { MenuFunction menuFunction; menuFunction = new MenuFunction(menuitemActionStr(My_Template), MenuItemType::Action); menuFunction.run(); }

Best regards,

Mohamed Amine MAHMOUDI

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