Open form on button click

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Posted on by _Charan

I need to open the form on button click
and inside clicked method i kept this code

Args args;
FormRun formRun;

Args = new Args(formStr(HcmGoalAddFromTemplate));

formRun = New FormRun(Args);
formRun.init();
formRun.run();
formRun.wait();

formname --------> HcmGoalAddFromTemplate

and I also tried using menuitem button with the same formname

always getting the same error as Object reference not set to an instance of an object.

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Ferhat.S 238 on at

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Hey Charan

I tested your code and its working. You might be clean solution and rebuild it.

Code probably not seeing your form.

Also please use Insert>Code paste your code here it makes easy to read.

Like:

Args args; FormRun formRun; Args = new Args(formStr(HcmGoalAddFromTemplate)); formRun = New FormRun(Args); formRun.init(); formRun.run(); formRun.wait();

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Suggested answer

Komi Siabi 13,109 Most Valuable Professional on at

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Hi _Charan,

Just like Ferhat, suggested build the solution and your custom module from the Extension -> Dynamics 365

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_Charan 10 on at

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ok got it thank you :)

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