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Disable custom FormMenuButtonControl on form

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Posted on by alinawaz

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Hi Community Experts,

I have a requirement where I need to disable a FormMenuButtonControl, it is a custom button coming from a different model.

I need to disable it on the Applications form inside Human Resource module.

But I am unable to get this control in the event handler, I am writing this inside On_Activated event handler of form data source.

But its returning an error that no such control exists on Form.

I tried with CoC as well, but its not working.

Looking forward to usual helpful responses on it.

Best Regards

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Arunraj Rajasekar 1,743 on at

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Have you included the other model where the menu item was created as a reference model in your model?

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Martin Dráb 237,807 Most Valuable Professional on at

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The first code snippet fails because no such control is available in the definition of HRMApplication form - it's added at runtime.

In the second code snippet, you're referring to a macro that you haven't defined anywhere in your class. The standard macro (SysSystemDefinedButtons) can't contain custom controls.

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alinawaz 209 on at

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goshoom How can I check which Macro to refer here ?

Its a different model altogether, I am not aware of its elements.

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Martin Dráb 237,807 Most Valuable Professional on at

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Maybe there is none - it's just your speculation that such a macro exists.

Look into the model that adds Dox42SystemDefinedButton to see whether the developer hard-coded the name, used a macro or a constant.

If you can't look into code, you can still look at model definitions to AOT, e.g. to know whether there is an AOT macro.

If you don't find anything, create a constant by yourself.

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GirishS 27,827 Moderator on at

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Hi Chota Hukam,

You can also create label id for control name and use it in your code. Like below.

[FormDataSourceEventHandler(formDataSourceStr(FormName, TableName), FormDataSourceEventType::Activated)] public static void TableName_OnActivated(FormDataSource sender, FormDataSourceEventArgs e) { FormRun frun = sender.formRun(); FormMenuButtonControl menuButton = frun.design().controlName("label Id You have created for the control") as FormMenuButtonControl; menuButton.visible(false); }

Thanks,

Girish S.

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