Number round off

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Posted on by Koti9999

Hi Experts,

I've a requirement to round off a number to nearest number.

weight is the field to round off.

like if the weight is 0.5 and below it should consider 0..if it is 0.75 and above the weight should round off to nearest number .i.e 1.

Pleese suggest on this.

Thank you in advance.

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GirishS 27,827 Moderator on at

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Hi koti,

You can make use of "decround" function.

Thanks,

Girish S

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Koti9999 55 on at

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Thank you Girish for your quick reply and suggestion !!

i wrote the code like below.

decRound(salesLine.ItemNetWeight, 0).

it is working (if the netweight is below 0.5 means 0.4..it is rounding off to 0).

one scenario it is failing.if itemNetWeight is 0.5 it is considering 1 .

the requirement is if the netweight is above 0.5 like 0.6 and above ..it is round off to 1.

the scenario will be like this.

0.1 = 0

0.2 = 0

0.3=0

0.4=0

0.5=0

0.6=1

0.7=1

0.8=1

0.9=1

1=1

please suggest on this.

Thank you in advance.

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Martin Dráb 237,768 Most Valuable Professional on at

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Which version of AX is it about?

Think carefully whether you really want a different way of round than used by the rest of AX. If you're sure, then you can either look for a pure X++ solution or utilize .NET. I'm not aware of any X++ function doing what you want, but you surely could implement this way of rounding by yourself. An easier (and safer, because it's tested) solution may be using System.Math::Round(). The third argument allow you to choose the rounding strategy.

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Komi Siabi 13,093 Most Valuable Professional on at

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Hi,

You can try this.

real _amount; // You can pass this a an argurment in your method real decimals; int intNum; _amount = 12.7; intNum = _amount; decimals = _amount - intNum; if (decimals <= 0.5) { _amount = intNum; } else { _amount = decRound(_amount,0); } Info(strFmt("%1",_amount));

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Koti9999 55 on at

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Thanks a lot Komi..

I applied the same logic, achieved the desired result.

Thanks,

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