how to breaking a string that concatenated using #newline

(0) Share

Report

Posted on by Community Member

I have a string was concatenated using #newline. It looks like following:

originalString= SerialNumber1 + #newline + SerialNumber2 + #newline + SerialNumber3 + #newline + SerialNumber4 +...+....

I need to get individual Serial Number from the originalString.

Note: the length of individual serial number is NOT same.

The problem is I don't know what exactly characters that defined in Macro #newline. I tried to debug still not display the characters. Otherwise I can use strScan function to get the position of the #newline. Then do a loop to get individual serial number.

Any advice would be appreciated

Anna

*This post is locked for comments

I have the same question (0)

All responses (3)

Answers (2)

Verified answer

Mea_ 60,284 on at

Like (0)

Report
You can try next code:

container c = str2con(originalString, #newline);

It will create a container where each element will be a serial number.

Then you can iterate through container using for loop to get individual elements.

Also you can look for #define.newline() in the top of you method\ class declaration to see what what characters are used or it could be included into macro library, but this library should be used in the top of the method \ class declaration as well (#macroLibraryName).

Was this reply helpful? Yes No
Verified answer

Hajish 460 on at

Like (0)

Report

check the below code may help to you.

List list = new List(Types::String);

container packedList;

ListIterator iterator;

str originalString ,result;

;

originalString= SerialNumber1 + #newline + SerialNumber2 + #newline + SerialNumber3 .... ;

list = strSplit(originalString , "\n");

iterator = new ListIterator(list);

while(iterator.more())

{

packedList += iterator.value();

iterator.next();

}

// "SerialNumber1" is stong to result.

//result= conPeek(packedList, 1);

Was this reply helpful? Yes No
Community Member on at

Like (0)

Report

Thank you Hajish and Ievgen ! That's really helpful.

Was this reply helpful? Yes No