how to breaking a string that concatenated using #newline

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I have a string was concatenated using #newline. It looks like following:

originalString= SerialNumber1 + #newline + SerialNumber2 + #newline + SerialNumber3 + #newline + SerialNumber4 +...+....

I need to get individual Serial Number from the originalString.

Note: the length of individual serial number is NOT same.

The problem is I don't know what exactly characters that defined in Macro #newline. I tried to debug still not display the characters. Otherwise I can use strScan function to get the position of the #newline. Then do a loop to get individual serial number.

Any advice would be appreciated

Anna

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Mea_ 60,284 on at

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RE: how to breaking a string that concatenated using #newline

You can try next code:

container c = str2con(originalString, #newline);

It will create a container where each element will be a serial number.

Then you can iterate through container using for loop to get individual elements.

Also you can look for #define.newline() in the top of you method\ class declaration to see what what characters are used or it could be included into macro library, but this library should be used in the top of the method \ class declaration as well (#macroLibraryName).

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Hajish 460 on at

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RE: how to breaking a string that concatenated using #newline

check the below code may help to you.

List list = new List(Types::String);

container packedList;

ListIterator iterator;

str originalString ,result;

;

originalString= SerialNumber1 + #newline + SerialNumber2 + #newline + SerialNumber3 .... ;

list = strSplit(originalString , "\n");

iterator = new ListIterator(list);

while(iterator.more())

{

packedList += iterator.value();

iterator.next();

}

// "SerialNumber1" is stong to result.

//result= conPeek(packedList, 1);

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Community Member on at

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RE: how to breaking a string that concatenated using #newline

Thank you Hajish and Ievgen ! That's really helpful.

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