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In a list view i set the main grid to editable and added a subgrid for an 1:n related entity. Than i added a command bar button. This should be visible whenever a parent record row or records in the subgrid are selected.
My Questions:
- Is this even possible? At the moment it seems only selected items in the subgrid seem to trigger the button to be visible?
- If its possible how to get the records/selected items by buttons javascript?
This describes best where i ended up finally BUT my original question actually was about how to grab both respectively each of the selections. Rows selcted on the top level and/or rows selected in one ore more of the embedded sub grids.
This doesnt seem to be possible (by javascript on command buttons). You can only work with the top level records - those are provided by the primary or selected grid or SelectedItemReferences/SelectedItemReferencesId.
I read somewehre that to achieve what i want some some could grab the collection and than post those top level record id to a plugin/flow (whatever) to, in a second query, get the related sub items.
Hi AndreasB83 ,
you can check the below article link
If this answer helps you, like and verify my answer
Hi,
I'm afraid it can't be done in a supported way.
The editable grid is enabled on the entity level cause its a view, not a form. I cannot figure out how to get the selected rows. I added a Command Bar Button and tried to get the rows from primarycontrol or selectedcontrol reference - nothing there.
To get the grid by name wont work because i dont know it and in html i only see sth like id="Grid67ab3cfa-a01d-13ec-81e7-648d6fe1536d_component"
In the form editor, add a new button to the form.
Set the Display Rule for the button to "Custom JavaScript."
In the Custom JavaScript area, enter the following code:
csharpCopy codefunction showHideButton() {
var gridControl = Xrm.Page.getControl("subgrid_name");
var selectedRows = gridControl.getGrid().getSelectedRows();
if (selectedRows.getLength() > 0) {
Xrm.Page.ui.controls.get("button_name").setVisible(true);
} else {
Xrm.Page.ui.controls.get("button_name").setVisible(false);
}
}
Replace "subgrid_name" with the name of your subgrid and "button_name" with the name of your button.
Save and publish the changes to the form.
Open the record form and select one or more rows in the subgrid.
The button should appear or disappear based on the number of selected rows.
Note that this code assumes that the subgrid is on the same form as the button. If the subgrid is on a different form, you may need to modify the code to reference the correct form and control names.
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André Arnaud de Cal...
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