Hiw to get the entity name from Grid view using JS

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Posted on by yify

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Hi,

I have a custom button on the opportunity entity view. On click of the button, I want to do some operation.

I am not sure how to get the entity name from the view through java script? Please advise the JS

Thanks

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a33ik 84,331 Most Valuable Professional on at

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James,

There is no need in any JS - you can pass entity name as a parameter to your on click handler - it's in the list of "CRM Parameters" of Ribbon Workbench.

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yify 1,023 on at

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Andrew, through Ribbon command I am adding the parameter - Primary Control and Selected Entity Type Name.

Could you please advise how my code should be at the grid level ?

Currently I have this code to open Quick Create at the Form Level and I want to implement at Grid Level by passing the entity name dynamically.

function openQuickCreate(PrimaryControl) {

var formContext = PrimaryControl;

var entityName = formContext.data.entity.getEntityName();

var entityFormOptions = {};

var formParameters = {};

entityFormOptions['entityName'] = entityName;

entityFormOptions['useQuickCreateForm'] = true;

entityFormOptions['createFromEntity'] = formContext.data.entity.getEntityReference();

Xrm.Navigation.openForm(entityFormOptions, formParameters).then(

function () {

},

function (error) {

});

}

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a33ik 84,331 Most Valuable Professional on at

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Pass the PrimaryControl as you are doing to access the context and pass Selected Entity Type Name, just add it to the handler function like:

function openQuickCreateFromGrid(PrimaryControl, SelectedEntityTypeName) {

//use SelectedEntityTypeName in your code

}

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Bipin D365 28,983 Moderator on at

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Hi,

You can get entity name by adding the two more parameters in ribbon workbench

1. PrimaryEntityTypeName

2. SelectedEntityTypeName

alert(PrimaryEntityTypeName); //Lead

alert(SelectedEntityTypeName);//competitor

I have your code on competitor subgrid which is available on Lead entity. Please see below result for different parameters from subgrid button.

function openQuickCreate(PrimaryControl,PrimaryEntityTypeName,SelectedEntityTypeName) { alert(PrimaryEntityTypeName); //Lead console.log(PrimaryEntityTypeName); alert(SelectedEntityTypeName);//competitor console.log(SelectedEntityTypeName); var formContext = PrimaryControl; var entityName = formContext.data.entity.getEntityName(); alert(entityName); console.log(entityName); var entityFormOptions = {}; var formParameters = {}; entityFormOptions['entityName'] = entityName; entityFormOptions['useQuickCreateForm'] = true; entityFormOptions['createFromEntity'] = formContext.data.entity.getEntityReference(); Xrm.Navigation.openForm(entityFormOptions, formParameters).then( function () { }, function (error) { }); };

If found helpful, Please mark my answer verified.

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yify 1,023 on at

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Thanks Andrew!! You are the CRM superman with all the powers :-)

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yify 1,023 on at

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Thanks Bipin for in detail steps, that helps.

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