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The value is not within the range. Acceptable values are within the range 0 – 2147483647.

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Posted on by Community Member Microsoft Employee

Hi All experts

i am facing a problem in creating new cheque book in cash and bank module.

the senario is i have a cheque book that starts with cheque no 8060539581 and ends at 8060539680.

so when i create a cheque book it gives me error "The value is not within the range. Acceptable values are within the range 0 – 2147483647."

i tried the solve this issue following the post https://blogs.technet.microsoft.com/dynamicsaxse/2011/04/15/issue-with-check-numbers-when-exceeding-the-upper-limit-of-a-32-bit-integer/

but when i payment journal i generate payment it is giving me this no -529395011 .

what should i do to resolve the issue . kindly help 0488.image.png

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Development / Customization / SDK

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Community Member Microsoft Employee on at

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RE: The value is not within the range. Acceptable values are within the range 0 – 2147483647.

To resolve this issue after following the above link make few more changes in code as give below

NumberSeq/numRemoveFormat

Change from :-

public static client server integer numRemoveFormat

Change to :-

public static client server int64 numRemoveFormat

VendOutPaym_Cheque/Dialog

startChequeNum = int642str(custVendCheque.parmFirstChequeNum());

VendOutPaym_Cheque/GetFromDialog

firstChequeNum = str2int64(startChequeNum);

regards
Verified answer

Community Member Microsoft Employee on at

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RE: The value is not within the range. Acceptable values are within the range 0 – 2147483647.

Issue has been Resolved

to do this do the following changes in the numRemoveFormat method of NumberSeq class as given below

From : -

public static client server Integer numRemoveFormat(Num num,
NumberSequenceFormat format
)
{
Integer x;
Integer val = #NextRecordNull;

if (!format)
return str2int(num);

............

To: -

public static client server int64 numRemoveFormat(Num num,
NumberSequenceFormat format
)
{
Integer x;
Integer val = #NextRecordNull;//0;

if (!format)
return str2int64(num);

..........

and forget not to follow the above link aswell.

Regards

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