Hi,
I would like to hide/show ribbon buttons based on a lookup field in my form.
My condition is If the lookup has a value of "Checked In" than button should not display otherwise it should display.
Thanks
Hi,
I would recommend to go for JS rule , where get the lookup text and return true/false. Here is the code -
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function RibbonShowHideButton() {
var returnResult = false;
var statusObj = Xrm.Page.getAttribute("taqi_checkoutstatus").getValue();
var statusVal = null;
if (statusObj != null) {
statusVal = statusObj[0].name;
if (statusVal.toLowerCase() == "checked in") {
returResult = true;
}
}
return returnResult;
}
Hi Thank you for your reply.
I have tried setting enable rule, but either the doesn't show at all or it shows all the time.
I have added valueRule in Enable Rules please refer screenshot
taqi_checkoutstatus is the lookup name, it has two values Checked In & Checked Out
I have also assigned this Enable Rule to Command and Command to Button.
Please Help.
Hi,
Use ribbon workbench enable rule or display rule.
[View:https://m.youtube.com/watch?v=wUiqaR9TruU]
[View:https://balugajjala.wordpress.com/2017/01/27/enabledisable-a-ribbon-button-dynamically-based-on-a-form-value]
[View:http://www.powerxrm.com/how-to-dynamically-enabledisable-ribbon-buttons-based-on-field-values/]
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